Parallel Networks

Example #1

Capacitors A, B and C are connected together in parallel. Together, they are equivalent to the single capacitor on the left labeled ‘ABC’. The capacitance of the entire three-capacitor network is equal to the sum of the individual capacitances in the network:

CABC = CA + CB + CC

where CABC, CA, CB and CC are the capacitances of capacitors ABC, A, B and C respectively. Substituting in the values from the diagram gives:

CABC = 4F + 3F + 2F = 9F.

Example #2

Capacitors A and B are connected together in parallel. Together, they are equivalent to the single capacitor on the left labeled ‘AB’. The capacitance of the entire two-capacitor network is equal to the sum of the capacitances of the individual capacitors:

CAB = CA + CB

where CAB, CA and CB are the capacitances of capacitors AB, A and B respectively. Substituting in the values from the diagram gives:

5F = CA + 4F.

Solving gives CA = 1F.