The definition of average acceleration is:
![]()
According to this definition, the vector average
acceleration is obtained by dividing a vector by a scalar.  Since the scalar (
)
is always positive, this definition indicates that the two vectors (
 and
)
have the same direction.  We would like to apply this definition to find the
direction of the acceleration at point D.  Then 
 and
 in
the definition correspond to an interval that spans point D, i.e., an interval with an initial point just before
point D and with a final point just after point D.  The diagrams below illustrate this idea graphically.
Suppose that a
ball rolls downhill along a straight track from point 1 to 2 to 3.  As the ball
rolls downhill, it speeds up.  Hence the lengths of the velocity arrows get
progressively longer.  
Recall that the change in velocity between the final point (point 3) and the initial point (point 1) is:
.
This is equivalent to saying that 
 is
the quantity that must be added to the initial velocity in order to obtain the
final velocity:  
![]()
The diagram at
right shows the vector (the red vector) that must be graphically added to
vector 
 to
obtain 
. 
Hence, the red vector must be 
. 
According to the definition of average acceleration,
![]()
Since 
 is
a positive scalar, the direction of the acceleration must be the same as the
direction of the change in velocity.  The relative magnitudes of 
 and
 depend
on the value of 
. 
If the interval
is short enough, then the average acceleration for the interval is equal to the
instantaneous acceleration at the midpoint of the interval, point 2.  This is
illustrated in the diagram at right.  Notice that the acceleration is in the
same direction as the velocity.  
In summary, the angle between the velocity and acceleration will be 0° whenever an object speeds up while moving in a straight line.