Resistors A, B and C are connected together in parallel. Together, they are equivalent to the single resistor on the left labeled ‘ABC’. The reciprocal of the resistance of the entire three-resistor network is equal to the sum of the reciprocals of the individual resistances in the network:

where RABC, RA, RB and RC are the resistances of resistors ABC, A, B and C respectively. Substituting in the values from the diagram gives:
.
Taking the reciprocal of both sides of the equation gives:
RABC = 2Ω.
Resistors A, B and C are connected together in parallel. Together, they are equivalent to the single resistor on the left labeled ‘ABC’. The reciprocal of the resistance of the entire two-resistor network is equal to the sum of the reciprocals of the resistances across the individual resistors:

where RABC, RA and RB are the resistances of resistors ABC, A and B respectively. Substituting in the values from the diagram gives:
.
Solving for 1/RA reveals:
.
Taking the reciprocal of both sides gives:
RA = 12Ω.
Note: The equation

gives a value for 1/Rparallel, not Rparallel. Hence, after plugging numbers into this equation, don’t forget to take the reciprocal of the answer to find Rparallel.